Banuiesc ca[latex]frac{a}{b}=frac{3}{5}, 5a=3b(1)\ ^{5)}frac{a}{2a+b}=}frac{5a}{2cdot 5a+5cdot b}=frac{3b}{6b+5b}=frac{3b}{11b}=frac{3}{11}.\ frac{a+b}{b}=^{5)}frac{a+b}{b}=frac{5a+5b}{5b}=frac{3b+5b}{5b}=frac{8b}{5b}=frac{8}{5}.\ frac{2a+b}{a+3b}=^{5)}frac{2a+b}{a+3b}=frac{2cdot5a+5b}{5a+3cdot5b}=frac{2cdot 3b+5b}{3b+15b}=frac{11b}{18b}=frac{11}{18}[/latex]